Radius of a circle is 9 cm and the angle of the sector is 70 ° . Find the area of the minor sector of the circle. π = 22 7

Given, Radius of a circle is 9 cm and the angle of the sector is 70 ° We know that area of minor sector = π r 2 θ 360 ° Therefore, area of minor sector = π × 9 2 × 70 ° 360 ° = 22 × 81 × 7 7 × 36 π = 22 7 = 49 . 5 cm 2 .

The radius of a circular park is 4 . 2 m . A path of 1 . 4 m width is made around the circular part. Find the area of the path.

Radius R of circular park = 4 . 2 m Therefore, Area of the circular park = π r 2 = 22 7 × 4 . 2 × 4 . 2 = 55 . 44 m 2 Width r of the circular path = 1 . 4 m Area of the circular park including the circular path = π R + r 2 sq . m = 22 7 × 4 . 2 + 1 . 4 2 = 22 7 × 5 . 6 × 5 . 6 = 98 . 56 m 2 Area of Path = Area of the circular park including the circular path - Area of the circular park = 98 . 56 - 55 . 44 = 43 . 12 m 2